hiho week 144 register

Ended

Participants:1096

Verdict:Accepted
Score:100 / 100
Submitted:2017-04-02 17:46:12

Lang:G++

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#include<iostream>
#include<math.h>
using namespace std;
int main(){
    long int n, m;
    cin >> n>>m;
    int prime1[100], prime2[100];
    int counter1 = 0, counter2 = 0;
    for(int i=2;i<=sqrt(double(n));i++)  
        if(n%i==0&&(n/=i))  
            prime1[counter1++] = i--;  
    prime1[counter1++] = n;  
    for(int i=2;i<=sqrt(double(m));i++)  
        if(m%i==0&&(m/=i))  
            prime2[counter2++] = i--;  
    prime2[counter2++] = m;  
    
    int bottom = 1;
    for(int i=0;i<counter1;i++)
    {
        int tmp1=1,tmp2=1;
        for(int j=i;j<counter1;j++)
            if(prime1[j] == prime1[i])
                tmp1++;
        for(int j=0;j<counter2;j++)
            if(prime2[j] == prime1[i])
            {
                tmp2++;
                prime2[j] = -1;
            }
        bottom *= max(tmp1, tmp2);
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